0.2x^2-0.08x=0

Solution for 0.2x^2-0.08x=0 equation:

0.2x^2-0.08x=0

a = 0.2; b = -0.08; c = 0;
Δ = b2-4ac
Δ = -0.082-4·0.2·0
Δ = 0.0064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.08)-\sqrt{0.0064}}{2*0.2}=\frac{0.08-\sqrt{0.0064}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.08)+\sqrt{0.0064}}{2*0.2}=\frac{0.08+\sqrt{0.0064}}{0.4}
$